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sqlserver常见面试题

发表于2014-08-20 10:12:35| --次阅读| 来源webkfa| 作者小猪仔

摘要:sqlserver常见面试题
1.用一条SQL语句 查询出每门课都大于80分的学生姓名

name   kecheng   fenshu 
张三     语文       81
张三     数学       75
李四     语文       76
李四     数学       90
王五     语文       81
王五     数学       100
王五     英语       90

A: select distinct name from table where name not in (select distinct name from table where fenshu<=80)

2.学生表 如下:
自动编号   学号   姓名 课程编号 课程名称 分数
1        2005001 张三 0001      数学    69
2        2005002 李四 0001      数学    89
3        2005001 张三 0001      数学    69
删除除了自动编号不同,其他都相同的学生冗余信息

A: delete tablename where 自动编号 not in(select min(自动编号) from tablename group by 学号,姓名,课程编号,课程名称,分数)

一个叫department的表,里面只有一个字段name,一共有4条纪录,分别是a,b,c,d,对应四个球对,现在四个球对进行比赛,用一条sql语句显示所有可能的比赛组合.
你先按你自己的想法做一下,看结果有我的这个简单吗?

答:select a.name, b.name 
from team a, team b 
where a.name < b.name


请用SQL语句实现:从TestDB数据表中查询出所有月份的发生额都比101科目相应月份的发生额高的科目。请注意:TestDB中有很多科目,都有1-12月份的发生额。
AccID:科目代码,Occmonth:发生额月份,DebitOccur:发生额。
数据库名:JcyAudit,数据集:Select * from TestDB

答:select a.*
from TestDB a 
,(select Occmonth,max(DebitOccur) Debit101ccur from TestDB where AccID='101' group by Occmonth) b
where a.Occmonth=b.Occmonth and a.DebitOccur>b.Debit101ccur

************************************************************************************

面试题:怎么把这样一个表儿
year month amount
1991   1     1.1
1991   2     1.2
1991   3     1.3
1991   4     1.4
1992   1     2.1
1992   2     2.2
1992   3     2.3
1992   4     2.4
查成这样一个结果
year m1 m2 m3 m4
1991 1.1 1.2 1.3 1.4
1992 2.1 2.2 2.3 2.4

答案一、
select year, 
(select amount from aaa m where month=1 and m.year=aaa.year) as m1,
(select amount from aaa m where month=2 and m.year=aaa.year) as m2,
(select amount from aaa m where month=3 and m.year=aaa.year) as m3,
(select amount from aaa m where month=4 and m.year=aaa.year) as m4
from aaa group by year


这个是ORACLE 中做的:
select * from (select name, year b1, lead(year) over
(partition by name order by year) b2, lead(m,2) over(partition by name order by year) b3,rank()over(
partition by name order by year) rk from t) where rk=1;

************************************************************************************

精妙的SQL语句!
精妙SQL语句 
作者:不详 发文时间:2003.05.29 10:55:05

说明:复制表(只复制结构,源表名:a 新表名:b)

SQL: select * into b from a where 1<>1

说明:拷贝表(拷贝数据,源表名:a 目标表名:b)

SQL: insert into b(a, b, c) select d,e,f from b;

说明:显示文章、提交人和最后回复时间

SQL: select a.title,a.username,b.adddate from table a,(select max(adddate) adddate from table where table.title=a.title) b

说明:外连接查询(表名1:a 表名2:b)

SQL: select a.a, a.b, a.c, b.c, b.d, b.f from a LEFT OUT JOIN b ON a.a = b.c

说明:日程安排提前五分钟提醒

SQL: select * from 日程安排 where datediff('minute',f开始时间,getdate())>5

说明:两张关联表,删除主表中已经在副表中没有的信息

SQL:

delete from info where not exists ( select * from infobz where info.infid=infobz.infid )

说明:--

SQL:

SELECT A.NUM, A.NAME, B.UPD_DATE, B.PREV_UPD_DATE

FROM TABLE1,

(SELECT X.NUM, X.UPD_DATE, Y.UPD_DATE PREV_UPD_DATE

FROM (SELECT NUM, UPD_DATE, INBOUND_QTY, STOCK_ONHAND

FROM TABLE2

WHERE TO_CHAR(UPD_DATE,'YYYY/MM') = TO_CHAR(SYSDATE, 'YYYY/MM')) X,

(SELECT NUM, UPD_DATE, STOCK_ONHAND

FROM TABLE2

WHERE TO_CHAR(UPD_DATE,'YYYY/MM') =

TO_CHAR(TO_DATE(TO_CHAR(SYSDATE, 'YYYY/MM') ¦¦ '/01','YYYY/MM/DD') - 1, 'YYYY/MM') ) Y,

WHERE X.NUM = Y.NUM (+)

AND X.INBOUND_QTY + NVL(Y.STOCK_ONHAND,0) <> X.STOCK_ONHAND ) B

WHERE A.NUM = B.NUM

说明:--

SQL:

select * from studentinfo where not exists(select * from student where studentinfo.id=student.id) and 系名称='"&strdepartmentname&"' and 专业名称='"&strprofessionname&"' order by 性别,生源地,高考总成绩

说明:

从数据库中去一年的各单位电话费统计(电话费定额贺电化肥清单两个表来源)

SQL:

SELECT a.userper, a.tel, a.standfee, TO_CHAR(a.telfeedate, 'yyyy') AS telyear,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '01', a.factration)) AS JAN,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '02', a.factration)) AS FRI,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '03', a.factration)) AS MAR,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '04', a.factration)) AS APR,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '05', a.factration)) AS MAY,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '06', a.factration)) AS JUE,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '07', a.factration)) AS JUL,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '08', a.factration)) AS AGU,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '09', a.factration)) AS SEP,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '10', a.factration)) AS OCT,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '11', a.factration)) AS NOV,

SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '12', a.factration)) AS DEC

FROM (SELECT a.userper, a.tel, a.standfee, b.telfeedate, b.factration

FROM TELFEESTAND a, TELFEE b

WHERE a.tel = b.telfax) a

GROUP BY a.userper, a.tel, a.standfee, TO_CHAR(a.telfeedate, 'yyyy')

说明:四表联查问题:

SQL: select * from a left inner join b on a.a=b.b right inner join c on a.a=c.c inner join d on a.a=d.d where .....

说明:得到表中最小的未使用的ID号

SQL:

SELECT (CASE WHEN EXISTS(SELECT * FROM Handle b WHERE b.HandleID = 1) THEN MIN(HandleID) + 1 ELSE 1 END) as HandleID

FROM Handle

WHERE NOT HandleID IN (SELECT a.HandleID - 1 FROM Handle a)


*******************************************************************************

有两个表A和B,均有key和value两个字段,如果B的key在A中也有,就把B的value换为A中对应的value
这道题的SQL语句怎么写?

update   b   set   b.value=(select   a.value   from   a   where   a.key=b.key)   where   b.id   in(select   b.id   from   b,a   where   b.key=a.key);

***************************************************************************

高级sql面试题

原表: 
courseid coursename score 
------------------------------------- 
1 java 70 
2 oracle 90 
3 xml 40 
4 jsp 30 
5 servlet 80 
------------------------------------- 
为了便于阅读,查询此表后的结果显式如下(及格分数为60): 
courseid coursename score mark 
--------------------------------------------------- 
1 java 70 pass 
2 oracle 90 pass 
3 xml 40 fail 
4 jsp 30 fail 
5 servlet 80 pass 
--------------------------------------------------- 
写出此查询语句

没有装ORACLE,没试过 
select courseid, coursename ,score ,decode(sign(score-60),-1,'fail','pass') as mark from course

完全正确

SQL> desc course_v 
Name Null? Type 
----------------------------------------- -------- ---------------------------- 
COURSEID NUMBER 
COURSENAME VARCHAR2(10) 
SCORE NUMBER

SQL> select * from course_v;

COURSEID COURSENAME SCORE 
---------- ---------- ---------- 
1 java 70 
2 oracle 90 
3 xml 40 
4 jsp 30 
5 servlet 80

SQL> select courseid, coursename ,score ,decode(sign(score-60),-1,'fail','pass') as mark from course_v;

COURSEID COURSENAME SCORE MARK 
---------- ---------- ---------- ---- 
1 java 70 pass 
2 oracle 90 pass 
3 xml 40 fail 
4 jsp 30 fail 
5 servlet 80 pass

*******************************************************************************

原表:

id proid proname 
1 1 M 
1 2 F 
2 1 N 
2 2 G 
3 1 B 
3 2 A 
查询后的表:

id pro1 pro2 
1 M F 
2 N G 
3 B A 
写出查询语句

解决方案

sql求解 
表a 
列 a1 a2 
记录 1 a 
1 b 
2 x 
2 y 
2 z 
用select能选成以下结果吗? 
1 ab 
2 xyz 
使用pl/sql代码实现,但要求你组合后的长度不能超出oracle varchar2长度的限制。 
下面是一个例子 
create or replace type strings_table is table of varchar2(20); 

create or replace function merge (pv in strings_table) return varchar2 
is 
ls varchar2(4000); 
begin 
for i in 1..pv.count loop 
ls := ls || pv(i); 
end loop; 
return ls; 
end; 

create table t (id number,name varchar2(10)); 
insert into t values(1,'Joan'); 
insert into t values(1,'Jack'); 
insert into t values(1,'Tom'); 
insert into t values(2,'Rose'); 
insert into t values(2,'Jenny');

column names format a80; 
select t0.id,merge(cast(multiset(select name from t where t.id = t0.id) as strings_table)) names 
from (select distinct id from t) t0;

drop type strings_table; 
drop function merge; 
drop table t;

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